25x+4=30x^2+6x

Solution for 25x+4=30x^2+6x equation:

25x+4=30x^2+6x

We move all terms to the left:

25x+4-(30x^2+6x)=0

We get rid of parentheses

-30x^2+25x-6x+4=0

We add all the numbers together, and all the variables

-30x^2+19x+4=0

a = -30; b = 19; c = +4;
Δ = b2-4ac
Δ = 192-4·(-30)·4
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-29}{2*-30}=\frac{-48}{-60}
=4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+29}{2*-30}=\frac{10}{-60}
=-1/6
$